6^2+b^2=^2

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Solution for 6^2+b^2=^2 equation:



6^2+b^2=^2
We move all terms to the left:
6^2+b^2-(^2)=0
We add all the numbers together, and all the variables
b^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{2}=0$

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